
Andrew M. answered 06/26/15
Tutor
New to Wyzant
Mathematics - Algebra a Specialty / F.I.T. Grad - B.S. w/Honors
Let's let F = Cost of a File, P = cost of a pen
Since 5 files cost $3 more than 3 pens we have:
5F = 3P +3
We also know that 3F + 6P = $17.40
We have two equations and two variables
5F = 3P +3 eqn 1
3F + 6P =17.4 eqn 2
5F-3P =3 by subtracting 3P from both sides of eqn 1
3F+6P=17.4
We need to eliminate one variable. If we multiply the new eqn 1 by 2 we will have -6P and
when we add the equations together it will eliminate the P variable so we can solve for F
10F-6P=6 (eqn 1)(2)
3F +6P=17.4
__________
13F = 23.40
F = 23.40/13
F = $1.80
Each file costs $1.80