The algebra problem example Y=2 is the type of problem is the operations is the reason to solve correctly

Question

y=2/x, y=3x

how do you solve the problem, thanks

 

Answer 1

If y=2/x and y=3x,

then 2/x = 3x

Given the above equation we can now solve for x.

1. 2/x = 3x
2. x² = 2/3
   
3. x = √2/3

Now that we have the value of x we can put this value into one of the given equations to find y:

• y = 2/x = 2/(√2/3) = 2.4494...
• Or, y = 3x = 3(√2/3) = 2.4494...

Hope you found this helpful!

Answer 2

Hi Lisa!

Looks like we have 3 functions: y=2 (a straight line across) ... y=3x (a rising line passing thru the origin) ... and y= 2/x (a curve that goes to the sky as x=>0 while flattening near y=0 as x=> gets big).

Where do the lines intersect? y=2 crosses them: 2= 3x ... x= 2/3 ... 2= 2/x ... x=1 ==> pts (2/3,2) (1,2) 

For last intersection, set 2/x = 3x ... x^2= 2/3 ... x= sqrt (2/3) ~ 1.4/1.7 ... x~ 0.8 ==> pt (0.8, 2.5) ... [There's also another cross for x<0 at (-0.8, -2.5) in the southwest quarter of the x-y grid for y=2/x curve]

Hope I understood the problem, ma'am ... :)