Arthur D. answered 06/09/15
Tutor
4.9
(338)
Forty Year Educator: Classroom, Summer School, Substitute, Tutor
x=# gallons used by the 30 mpg car
y=# gallons used by the 40 mpg car
30x+40y=2050
x+y=55
simplify the first equation
3x+4y=205
x+y=55
x=55-y
substitute
3(55-y)+4y=205
165-3y+4y=205
165+y=205
y=205-165
y=40 gallons
x+40=55
x=55-40
x=15 gallons