Inactive Tutor answered 07/16/13
Use vertex form,
y = a(x-1)^2 + 20
Plug in (0, 16),
16 = a + 20
==> a = -4
y = -4(x-1)^2 + 20
To find the x-intercept, let y = 0.
0 = -4(x-1)^2 + 20
x = 1 +/- sqrt(5)
Answer: (1 +/- sqrt(5), 0)
Chris P.
asked 07/16/13Find the x-intercepts of the parabola with vertex (1,20) and y-intercept (o,16). Write your answer in this form: (x1,y1),(x2,y2). If necessary, round to the nearest hundredth.
Inactive Tutor answered 07/16/13
Use vertex form,
y = a(x-1)^2 + 20
Plug in (0, 16),
16 = a + 20
==> a = -4
y = -4(x-1)^2 + 20
To find the x-intercept, let y = 0.
0 = -4(x-1)^2 + 20
x = 1 +/- sqrt(5)
Answer: (1 +/- sqrt(5), 0)
Get a free answer to a quick problem.
Most questions answered within 4 hours.
Choose an expert and meet online. No packages or subscriptions, pay only for the time you need.