In Δ PQR, right-angled at Q, PR + QR = 25 cm and PQ = 5 cm. Determine the values ofsin P, cos P and tan P

PR+QR=25

PR is the hypotenuse, PQ and RQ are the legs of the right angled triangle

PQ=5 (given)

Applying Pythagorean theorem we have PR^{2} - QR^{2} = PQ^{2 }= 25^{
}

(PR^{2} - QR^{2})/(PR+QR) = PR-QR = 25/25 = 1

PR+QR = 25

PR-QR = 1

Solving for PR and QR we have PR = 13 and QR = 12

Sin(P) = QR/PR = 12/13

Cos(P) = PQ/PR = 5/13

Tan(P) = QR/PQ = 12/5

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