Jass S.

asked • 06/20/13

Log Confusion...Please explain this equation

lg(N^2+1)===??????????????? simplify

 

lg(N^2+1)/lgN    ===?????????

 

lg x/lg y===lg x - lg y              (right or wrong ??????????)

     

 

 

 

Please simplify this equation 

John R.

I am not sure what you are asking.  Are these three different problems?

 

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06/20/13

3 Answers By Expert Tutors

By:

Yitzhak S. answered • 06/20/13

Tutor
4.8 (4)

Johns Hopkins Engineer, Specializing in Math and Science.

Jorge M. answered • 06/20/13

Tutor
New to Wyzant

Mathematics + Physics+ Computer Science

Yitzhak S.

Your assumptions are incorrect: log(x * y) = log (x) + log(y). The reverse is not true. In the same way, log (x/y) = log(x) - log(y). Again, the way you have it is not the same thing, and not correct.

You can check this by plugging in numbers.

If x is 1000, and y is 100, then according to you, log(1000)/log(100) would equal log(900). log(1000) = 3, log(100) = 2, and 3/2 = 1.5. Log(900) is  NOT 1.5 (it is about 2.95).

HOWEVER log(1000/100) is equal to log(1000)-log(100). Log(10) = 1. Log(1000)-log(100)= 3-2=1.

You can confirm the rule for multiplication in the same way!

Since lg(1) = 0, by your logic, the answer to the first question would always be 0 (since anything times zero is zero). This is not true.

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06/20/13

Jorge M.

You're right, I did get it mixed up, sorry about the confusion John. Thanks for pointing that out Yitzhak! Jumped the gun on that one, I don't see any simple ways to simplify the given equation unless we can make an approximation as shown below.

We can use the base changing formula log10(a)/log10(b)= logb(a)

For our given problem we are given:   log(N2+1)/log(N) = logN(N2+1)

If we have large N we can make an approximation: logN(N2+1)˜logN(N2) = 2

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06/20/13

Jorge M.

Sorry, *Jass*

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06/20/13

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