The length of a rectangle is 3 times its width. If the perimeter of the rectangle is 80 ft, find its area

Question

The length of a rectangle is 3 times its width. If the perimeter of the rectangle is 80 ft, find its area

Answer 1

Let width = x

Let length = 3x

Area = length × width

Perimeter = 2(length) + 2(width)

 

 

First find the perimeter.

 

2(3x) + 2(x) = 80

 

6x + 2x = 80

8x = 80

  x = 10

 

Substitute this value of x in the length and width.

 

width = 10 ft

length = 30 ft

 

 

Next, multiply these values to find the area.

 

Area = 30 ft × 10 ft

Area = 300 ft²

Answer 2

w=width

3w=length

P=2l+2w

80=2(3w)+2w

80=6w+2w

80=8w

w=80/8

w=10 feet

3w=30 feet

A=l*w

A=30*10

A=300 square feet