how much water must be added to 12 quarts of a10% solution of salt and water to reduce to a 6% solution

Question

Mixture word problem 

Answer 1

Hi Nida,

 

Let x = quarts of water to be added

 

so then

 

12* 10%  + x * 0%  = (12+x) * 6%   (this says 12 quarts of 10% solution + x quarts of 0%(water) equals the new total (12+x) of a 6% solution

 

1.2 = .72 + .06x

 

.48 = .06x

 

x = 8   (quarts of water to be added

 

Hope this helps