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help in algebra 1

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 If questions is rewritten saying a CD cost is 3 books. and on 3 books and 2 CD you spent $18. Then we can solve the problem as below.

b = price of books & c= price of cds

3b + 2c = 18 

c = 3b

I am using substitution to solve

3b + 2(3b) = 18    I solved for one variable

3b +6b = 18

9b = 18

b = $2  Cost of the book

c = $6  Cost of the CD