Kevin K. answered 05/11/13
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Speed is the magnitude of the velocity function
so first we need to find v(t) = r ' (t)
r ' (t) = 3e^3t i - 3e^-3t j + (3te^3t + e^3t)k
so v(0) = r ' (0) = 3e^0 i - 3^0 j + (3*0e^0 + 3^0)k = 3i - 3j + k
so then magnitude of velocity at t = 0 is sqrt(3^2 + (-3)^2 + 1^2) = sqrt(9+9+1) = sqrt19