Find the normal vector to the plane?

Question

Find the normal vector to the plane 3x+2y+6z=6.

Answer 1

To find the normal vector to a plane, all we have to do is look at the coefficients

So the normal vector is 3i + 2j + 6k

Answer 2

3 vectors defining the plane are ,<2, 0, 0>, <0, 3, 0>, <0, 0, 1>

x1 - x2= <2, -3, 0>

x1 - x3= <2, 0, -1>

 i         j          k

2        -3         0                    = 3i + 2j + 6k

2         0        -1