Heidi A. answered 05/10/13
Heidi - Engineer, Teacher, & Tutor of Math and Technology
You know, sometimes problems just aren't presented well. Remember they're presenting a relationship about the number of boxes needed, but what's up with this "20"? Where did it come from?! What I like to do is create my own problem from the data:
If I want to store at least 200 books, I know that 20 bks/lg·x lg + 10 bks/sm ·y sm > 200 (It should be ≥ in my opinion since the problem says "at least", but you can only argue so much.) Hmmm, look what happens if we simplify.
20x + 10y > 200; factor 10 from both terms on the left
10(2x+y) > 200; divide both sides by 10
2x+y > 20 PROVEN! You're awesome!
Is this useful? Sure. Let's say you have 5 large boxes left. You'll need y>20-2(5) or at least 10 small boxes. 5lg(20bk/lg)+10sm(10bks/sm) = 100 bks + 100 bks = 200 bks. So you can check your inventory and see if you've got enough small boxes to get these suckers put away!