Shashikant K. answered 04/17/15
Tutor
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Algebra I & II, and Mathematics for Grade 1 to 12
When x=20 the y=40 and z=16.
x=16ky where k is a constant. So 10=16*k*20, Therefore k=1/32. So x=20 y=40.
z=qy.y, when y=20, z=4. So 4=q.20.20 Therefor q=1/100 and when y=40, z=40.40/100 that is z=16
(x,y,z)=(20,40,16)
Shashikant K