Two jets leave an air base at the same time and travel in opposite directions, what is the rate of each jet?

Question

Two jets leave an air base at the same time and travel in opposite directions. One jet travels 83 mph slower than the other. If the two jets are 6005 mi apart after 5 hours, what is the rate of each jet?

Answer 1

distance=rate*time

d=r*t

d=r*5

d=(r-83)*5

6005=r*5+(r-83)*5

6005=5r+5r-415

6005=10r-415

6005+415=10r

6420=10r

r=6420/10

r=642 mph for the faster jet

r-83=642-83=559 mph for the slower jet