
Ayush S.
asked 04/14/15Mean Question
The average of n numbers x^1, x^2, x^3, ........, x^n is M. If x^n is replaced by x', then new average
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1 Expert Answer
Edward C. answered 04/14/15
Tutor
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Caltech Grad for math tutoring: Algebra through Calculus
If the average of n numbers is M then the sum of the n numbers is n*M, so
x^1 + x^2 + x^3 + ... + x^(n-1) + x^n = n*M
If x^n is replaced by x' then x^n is subtracted from the sum and x' is added so
x^1 + x^2 + x^3 + ... + x^(n-1) + x' = n*M - x^n + x'
There are n numbers in the sum on the left so the new average is the sum divided by n which is
(n*M - x^n + x')/n = M - x^n/n + x'/n = M + (x' - x^n)/n
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Jon P.
04/14/15