Your suppose to solve it, take the answer and break it down into 3 binomials i think so the answer choices would be
A. -(x-3)(x+3)(x+9) etc..
Your suppose to solve it, take the answer and break it down into 3 binomials i think so the answer choices would be
A. -(x-3)(x+3)(x+9) etc..
27(x - 3) + 6x(x - 3) - x^{2}(x - 3)
All three terms share a common factor, which is x - 3 . So if we factor out this binomial from all three terms, we get
(x - 3)(27 + 6x - x^{2})
Now we can further factor the trinomial and arrive at the following:
(x - 3)(3 + x)(9 - x)
Rearranging the terms in the last two binomials so that the variable, x, is the first terms we get...
(x - 3)(x + 3)(-x + 9)
Factor out a -1 from the last binomial:
(x - 3)(x + 3)(-1)(x - 9)
(-1)(x - 3)(x + 3)(x - 9)
-(x - 3)(x + 3)(x - 9)
27(x-3) + 6x(x-3) - x^2(x-3)
= (x - 3)(27 + 6x - x^2) ; factor out (x - 3)
= - (x - 3)(x^2 - 6x - 27) ; re-arrange with - sign out
= - (x - 3)(x + 3)(x - 9) ; factor