Your suppose to solve it, take the answer and break it down into 3 binomials i think so the answer choices would be

A. -(x-3)(x+3)(x+9) etc..

Your suppose to solve it, take the answer and break it down into 3 binomials i think so the answer choices would be

A. -(x-3)(x+3)(x+9) etc..

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*27***(x - 3)** *+ 6x***(x - 3)**
*- x*^{2}**(x - 3)**

All three terms share a common factor, which is **x - 3** . So if we factor out this binomial from all three terms, we get

**(x - 3)***(27 + 6x - x*^{2}*)*

Now we can further factor the trinomial and arrive at the following:

**(x - 3)***(3 + x)(9 - x)*

Rearranging the terms in the last two binomials so that the variable, x, is the first terms we get...

(x - 3)*(x + 3) (-x + 9)*

Factor out a **-1** from the last binomial:

(x - 3)(x + 3)**(-1)(x - 9)**

(-1)(x - 3)(x + 3)(x - 9)

** -(x - 3)(x + 3)(x - 9)**

27(x-3) + 6x(x-3) - x^2(x-3)

= (x - 3)(27 + 6x - x^2) ; factor out (x - 3)

= - (x - 3)(x^2 - 6x - 27) ; re-arrange with - sign out

= - (x - 3)(x + 3)(x - 9) ; factor