Mark M. answered 04/04/15
Tutor
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Retired Math prof with teaching and tutoring experience in trig.
By the Pythagorean Theorem, (x-2)2 + (x-2)2 = (x+4)2
x2 - 4x + 4 + x2 - 4x + 4 = x2 + 8x + 16
x2 - 16x - 8 = 0
x = 16 ± √[(-16)2 - 4(1)(-8)]
2(1)
= 16 ± √288
2
= 16 ± 12√2
2
= 8 ± 6√2 ≈ 16.48, -0.48
Since a negative value for x makes no sense in this context,
x = 8 + 6√2