lim (1/n+1 + 1/n+2 + ......... 1/2n) is equal to n→∞ a) 0 b) 1 c) 2 d) loge2 the answer is loge2 , bt howi cant understand, it should be...
lim (1/n+1 + 1/n+2 + ......... 1/2n) is equal to n→∞ a) 0 b) 1 c) 2 d) loge2 the answer is loge2 , bt howi cant understand, it should be...
What is the smallest value of a if the area under the curve y=e^(ax) from -infinity to 4 is 11? I cannot seem to arrive at the answer using integrals. Please help.
Determine whether the function is continuous or discontinous. Justify your reasoning. If discontinuous, identify points of discontinuity. 2-X^2...
lim h(t), where h(t)= (cos(t)-1)/(t^2). note that h(t) is even, that is, h(t)=h(-t). t--0 t= (+-)0.002 (+-)0.0001 (+-)0.00005 (+-)0...
It is one of the items in my problem set. I am enroled at a distance learning program and I see my professor rarely. I hope someone could help.
limit as n goes to infinity Σ [i=1, n] (cosx1/x1) Δx, [3Π,4Π] answer is ∫[3Π,4Π] ... ? Need help understanding!
Calculate: lim x->0 (sin4x2)/(x2) I've seen an explanation of the problem and it says the answer is 4. I just don't understand what you're supposed to do after u-substitution...
The acceleration due to gravity, g; is given by g = GM / r2 ; where M is the mass of the earth, r is the distance from the center of the earth, and G is the universal gravitational...
The de?finitions of derivative of two functions f and g are given by: f' (x) = lim f(x + Δx) - f (x) / Δx , g'(x) = lim g(x + Δx) - g(x) / Δx ...
lim x -> 0 , x/lnx lim x -> ∞ , logx/x lim x -> 0 , xlogx
I was unable to find a method online how to use the δ-ε definition of a limit to prove that the limit is L for a function which includes an absolute value. My function is ...
lim n-- infinity)(n2- 3sqr(n4-n6)) . I get infinite from this, and I have the solution written which is 1/3. Help me please!
Evaluate lim ((x^(1/n)-a^(1/n))/(x-a)) as x->a and lim ((x^n-a^n)/(x-a)) as x->a? I didnt learn l'hopital's rule
lim (ln(x^-1))^x x->0+
Please explain how to do this
lim (x--> p/3) sin(x-3)/(4cos2-1)
limn->infinite[ (-1)n/(n3-12)} I dont know what to do with (-1)n, if it's equal to infinite then if I divide by n3, it's infinite over infinite. I dont understand :S. And the question...
How to get 1/3a^(2/3)
lim (8)/(xcot5x)=? x→0
limit as x--> 0 (8/(xcot5x)