lim n-- infinity)(n2- 3sqr(n4-n6)) . I get infinite from this, and I have the solution written which is 1/3. Help me please!
lim n-- infinity)(n2- 3sqr(n4-n6)) . I get infinite from this, and I have the solution written which is 1/3. Help me please!
Evaluate lim ((x^(1/n)-a^(1/n))/(x-a)) as x->a and lim ((x^n-a^n)/(x-a)) as x->a? I didnt learn l'hopital's rule
Please explain how to do this
lim (x--> p/3) sin(x-3)/(4cos2-1)
limn->infinite[ (-1)n/(n3-12)} I dont know what to do with (-1)n, if it's equal to infinite then if I divide by n3, it's infinite over infinite. I dont understand :S. And the question...
How to get 1/3a^(2/3)
I was unable to find a method online how to use the δ-ε definition of a limit to prove that the limit is L for a function which includes an absolute value. My function is ...
lim (8)/(xcot5x)=? x→0
limit as x--> 0 (8/(xcot5x)
limit as x approaches 0 (8/(xcot5x))
The solutions (x,y) of the equation x^2 + 16y^2 = 16 form an ellipse circle Consider the point P ( in the positive x-yplane), with x-coordinate 1. a) Let h be a small non-zero number and form...
fin the limit of (1-cos2x-cos4x)/x as x->0 and show all work!
Find as limit x approaches 0 for sqrtx sin (2pi/x)
lim ...
find lim x --- -1 6x+5 _______ ...
lim cosθ-(1/√2)/(θ-π/4) θ→π/4 I rewrote θ as h so I have lim which is cosh-(1/√2)/h-(π/4) ...
why would the upper range be "≤ 2√x"??
Find the values of a and b that make the function f(x) continuous if: f(x)=sinx/x for x less than zero ax+b for x greater than or equal to zero and less than or equal to two x^2+3...
lim (x+1)/(x+2) x->3+ how would a + or - on c change anything when solving without a graph?
Find the x-value-(s) for which the following function is discontinuous. For each discontinuity state the type as either removable or non-removable. Please show some of the steps.