(-x*x*x+2*x*x)*e(-x+1)

(-x*x*x+2*x*x)*e(-x+1)

limit x tending to pi/2 ((1-(sinx)^sinx/((cos x)^2))limit x tending to pi/2 ((1-(sinx)^sinx/((cos x)^2))limit x tending to pi/2 ((1-(sinx)^sinx/((cos x)^2))

Let f(x)=x^3 when x is less than or equal to 2 and x-2 when x is greater than 2 (Piecewise function) What is the limit of x approaching 2 from the right side? Explain. I'm pretty...

limit as x approaches 9 at (x+5)/[(sqrt of x)-3] Why does this limit not exist?

lim as x tends to infinity of (1/5)ln(x/2x+5) The answer is -ln(2/5) . I dont understand how you get this.

Background information: nsin(1/n) diverges using the Test for Divergence. I was playing around on my calculator and I noticed that no matter what term number you use the output...

if the limit as x approaches 5 of f(x) = 0 and lim as x approaches 5 of g(x) equals 0 the find functions of f(x) and g(x) that would make the limit as x approaches 5 of f(x)/g(x) = 10 please...

So I was trying to find a solution to some unusual integral. Let say int(e^(sinx) dx). And then it came to my mind that it might exist a well defined function of x, f(x), such that lim n-> infinity...

limx-->positive infty sqrt(3x^5-2x)-sqrt(3x^5-7x) I first rationalized the whole thing. After this , i divided the top and the bottom by x^5 but the answer I got is not the...

Lt x tends to infinity sin(a/2^x)/sin(b/2^x)

limx-->positive infty sqrt(9x^3+x) -x^3/2) The only one thats under the square root is 9x^3+x I dont know how to solve is

lim x--> -infty ( 4x-3)/(25x^2+4x) Im not sure if this is a legititamte way of solving but heres how I attempted: I took the highest power at the bottom and top and...

The value of limx→∞ (3^x + 3^2x)^(1/x)

lim as x tends to positive infinity sqrt(3x^5-2x)-sqrt(3x^5-7x) Answer I got : (5)/(2√3)

lim 1 1 2 3 n — [ (—)9+(—)9+(—)9+...

limx-->2 ( sin(2x-4)/(x-2)

limx--> 0+ (1/sqrtx) - ( 1/sqrtx^2+x) Please show me steps. Im really confused.

lim as x tends to positive infty (x+√x)/(x2+x+1)

Please, i got an exam tmr and i have to solve this asap

limit n->infinity −(7.2^n+5.5^n/7+3.5^(n+1))?