lim 1 1 2 3 n — [ (—)9+(—)9+(—)9+...

lim 1 1 2 3 n — [ (—)9+(—)9+(—)9+...

limx-->positive infty sqrt(3x^5-2x)-sqrt(3x^5-7x) I first rationalized the whole thing. After this , i divided the top and the bottom by x^5 but the answer I got is not the...

limx-->positive infty sqrt(9x^3+x) -x^3/2) The only one thats under the square root is 9x^3+x I dont know how to solve is

lim x--> -infty ( 4x-3)/(25x^2+4x) Im not sure if this is a legititamte way of solving but heres how I attempted: I took the highest power at the bottom and top and...

The value of limx→∞ (3^x + 3^2x)^(1/x)

lim as x tends to positive infinity sqrt(3x^5-2x)-sqrt(3x^5-7x) Answer I got : (5)/(2√3)

Show that sup(−xn) = −inf xn for any sequence (xn) in ¯ℜ (Real numbers symbol with a line on its top). Conclude that lim sup(−xn) = −lim inf xn.

A sequence xn is said to be dominated by a sequence yn if xn ≤ yn for each n. Show that, if so 1. inf xn ≤ inf yn, 2. sup xn ≤ sup yn, 3. lim inf xn...

limx-->2 ( sin(2x-4)/(x-2)

I dont undestand why te answer to this is 1/sqrt2 limx-->0 ( sqrt2+x^2)-(sqrt2-x^2) /(x^2)

limx--> 0+ (1/sqrtx) - ( 1/sqrtx^2+x) Please show me steps. Im really confused.

lim as x tends to positive infty (x+√x)/(x2+x+1)

limit n->infinity −(7.2^n+5.5^n/7+3.5^(n+1))?

Please, i got an exam tmr and i have to solve this asap

lim x -> 0 (cos(5x) - 1)/sin(7x)

Limx--->(pi/2) secx-tanx How do i solve this without hopital rule?

lim--> -infty (4+6e^2t)/(5-9e^3t) I really dont understand it

Find the limit as x approaches π (pi).

Im pretty sure the first one is a composite limit and the next i just have to find the limit lim(x→0) [cos?(x)]/[ln?(sin?(x) )] lim(x→∞) [(e^x)/(1-e^x...

lim as x tends to pi/2 cotx/cscx. (cos/sin)/(1/sin) = cosx = 0

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