Anthony W. answered 04/04/15
Tutor
5
(12)
Experienced Math Tutor for K-12/College students
Hi Amanda,
It may look complicated but is actually quite simple if you know your trig identities
first you want to expand the left side so:
LHS (left hand side)
=(csc(x)+cot(x))(csc(x)-cot(x)
=csc2(x)+csc(x)cot(x)-csc(x)cot(x)-cot2(x)
=csc2(x)-cot2(x)
=1 (because of trig identities)
= RHS (right hand side)
if you don't know that csc2(x)-cot2(x)=1, then you can start with sin2(x)+cos2(x)=1, so
sin2(x)+cos2(x)=1 (divide both sides by sin2(x)
1+cos2(x)/sin2(x)=1/sin2(x) (cos2(x)/sin2(x)=cot2(x) and 1/sin2(x)=csc2(x))
1+cot2(x)=csc2(x)
1=csc2(x)-cot2(x)
hope this helps