z^{3 }^{ }Times 5 35z 4z^{2} 4/8/2013 | Courtnee from Mitchell, IN | 1 Answer | 0 Votes Mark favorite Subscribe Comment
You have 3 z's on the top and 3 z's on the bottom so they cancel out each other, leaving you with 5/35, which is 1/7. 4/9/2013 | Luke B. Comment Comments Thanks again Luke, but that's not one of the multiple choices. I have: a.) z^3/28z^2 b.) 1/28 c.) 1/28z 4/9/2013 | Courtnee from Mitchell, IN I neglected the 4 in the denominator on my first look at it. But my method still applies: cancel the z's, then reduce what you have left of the fraction. 4/9/2013 | Luke B. Comment
Thanks again Luke, but that's not one of the multiple choices. I have: a.) z^3/28z^2 b.) 1/28 c.) 1/28z 4/9/2013 | Courtnee from Mitchell, IN
I neglected the 4 in the denominator on my first look at it. But my method still applies: cancel the z's, then reduce what you have left of the fraction. 4/9/2013 | Luke B.
Comments
Thanks again Luke, but that's not one of the multiple choices. I have:
a.) z^3/28z^2
b.) 1/28
c.) 1/28z
I neglected the 4 in the denominator on my first look at it. But my method still applies: cancel the z's, then reduce what you have left of the fraction.