A sample of Argon has a volume of 4.3 mL at 24°C. At what temperature in degrees Celsius is will it have a volume of 19.3 mL?

Question

A sample of Argon has a volume of 4.3 mL at 24°C. At what temperature in degrees Celsius is will it have a volume of 19.3 mL?

Answer 1

We are given and initial volume of 4.3 ml (V1) and an initial temperature of 24ºC (T1). We are asked to find the final temperature (T2) when the final volume (V2) is 19.3 ml.

Since the pressure is constant, we can use Charles's Law:

V1/T1 = V2/T2 but we must put the temperature in Kelvin

V1 = 4.3 ml

T1 = 24ºC + 273 = 297K

V2 = 19.3 ml

T2 = ?

V1/T1 = V2/T2

4.3 ml / 297K = 19.3 ml / T2

T2 = 1330K

To convert to ºC we subtract 273

T2 = 1060ºC

Answer 2

the underlying formula you want to use here is

V1/T1 = V2/T2

solving for T2 in this scenario yields

T2 = (19.3 mL) x (297.15 K) / 4.3 mL = 1333.72 K

then back into degrees Celsius

1333.72 K - 273.15 = 1060.57 degrees Celsius