Denise G. answered • 04/09/25
Algebra, College Algebra, Prealgebra, Precalculus, GED, ASVAB Tutor
For the 1st composite figure:
Total Area = Area of the Kite + Area of the Triangle
Total = pq/2 + 1/2bh (p and q are the lengths of the diagonals)
We see that the shorter diagonal has 6 on the left side. So the total length would be 12 for that.
On the bottom left, using the Pythagorean theorem we can find the bottom diagonal measurement
62+y2=102
36+y2=100
y2=100-36
y2=64
y=8
The top measurement of the diagonal would be 6, since it is a 45-45-90 triangle. The total length of that piece is 14
Next, lets look at the triangle. The height of that would be 8, the same measurement of the bottom piece of the kite. So now, we have all the measurements needed.
Total = (12)(14)/2 + 1/2(12)(8)
Total = 84+48
Total Area = 132 units2
Total Area = Area of the Kite + Area of the Triangle + Area of the Trapezoid
Will focus on the Trapezoid
A = (a+b)h/2 a and b are the measurements of the top and bottom, b is the height. We have all this information.
A = (12+24)(10)/2 = 90
New Area = 132 + 90 = 222 units2
Mark M.
Doug C. Adhering to the "do not assume it is because it looks like it is" mantra, unless the problem states it is a kite or that the diagonals are perpendicular, nothing in the diagram supports that notion.04/09/25
Denise G.
04/09/25
Mark M.
Denise G. So would I. Assumptions are never allowed in proofs, Geometric or Algebraic.04/10/25
Brenda D.
04/10/25
Brenda D.
04/10/25
Doug C.
I am wondering, based on the diagram are we completely sure that we have a kite and right triangles? Shouldn't the diagram include an indication that the diagonals are perpendicular?04/09/25