How many grams are in 5.58 x 10^24 formula units of tin (IV) nitrate?

Question

How many grams are in 5.58 x 10^24 formula units of tin (IV) nitrate?

Answer 1

In order to compute this I would divide by Avogadro's number in order to get the number of moles:

5.58 x 10^24 / 6.022 x 10^23 = 9.27 mol

From there then you want to multiply by the molar pass of tin(IV) nitrate, which is 366.73 g/mol

9.27 mol x 366.73 g/mol = 3398.08 g

Answer 2

Tin(IV) nitrate = Sn(NO₃)₄

Molar mass Sn(NO₃)₄ = 366.7 g/mol (hopefully you know how to find molar mass)

Use the following conversions and dimensional analysis to find the answer:

1 mol Sn(NO₃)₄ = 366.7 g

1 mol Sn(NO₃)₄ = 6.022x10²³ formula units (Avogadro's number)

5.58x10²⁴ formula units x 1 mol/6.022x10²³ formula units x 366.7 g/mol = 3398 g = 3.40x10³ g (3 sig.figs.)