Use this form of the law of cosines:
cos A = (b2 + c2 - a2) / (2bc)
a is the side across from (or opposite to) angle A.
The result is 98.96 degrees, approximately, or 99.0 degrees to one decimal place.
If you need the details, please let me know.
Kalea R.
asked 11/24/24A triangle is given.
𝜃 = ?°
Use this form of the law of cosines:
cos A = (b2 + c2 - a2) / (2bc)
a is the side across from (or opposite to) angle A.
The result is 98.96 degrees, approximately, or 99.0 degrees to one decimal place.
If you need the details, please let me know.
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