Find the slope of a line perpendicular to the line whose equation is 3, x, plus, y, equals, minus, 93x+y=−9. Fully simplify your answer.

Answer 1

Let's rewrite the equation of the line into slope-intercept form:

3x + y = -9

y = -3x - 9 [subtract 3x from both sides]

The slope of this line is -3. Remember, the slope of the line that is perpendicular to this one is equal to the negative reciprocal of the slope of the first line. Therefore, the slope of the perpendicular line is 1/3.

Hope this was helpful.