Inactive Tutor answered 02/10/26
x = 11/cos55 = 11sec55
use law of sines
x/sin90 = 11/sin(90-55)= 11/sin45
x/1=x =11/sin45= 11/cos55
Mark M.
asked 11/02/24Inactive Tutor answered 02/10/26
x = 11/cos55 = 11sec55
use law of sines
x/sin90 = 11/sin(90-55)= 11/sin45
x/1=x =11/sin45= 11/cos55
We know the adjacent and the angle, and we want to solve for the hypotenuse
adj / hyp = cos(55°)
11/x = cos(55°)
x = 11/cos(55°)
Inactive Tutor answered 11/02/24
In relation to the 55 degree acute angle of the right triangle, the side with length 11 is the adjacent leg, the side with length x is the hypotenuse. By the way the other acute angle has a measure of 35 degrees. If you have learned the reciprocal trig ratios (secant, cosecant, cotangent), then there are 4 possible equations:
cos(55) = 11/x
sec(55) = x/11
sin(35) = 11/x
csc(35) = x/11
Let's use the 2nd equation above to solve for x:
sec(55) = x/11
x = 11 sec(55)
Using the 1st equation:
cos(55) = 11/x
x cos(55) = 11
x = 11/cos(55)
Visit this Desmos graph (by selecting the URL, right-clicking, and selecting "go to...") to see the results of solving all 4 equations for x.
desmos.com/calculator/ujrl0tefwc
Note that the wrench icon on this graph was used to set the calculator to degree mode.
x = 11sec(55)
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