The image of the point (9,−3) under a translation is (4,1). Find the coordinates of the image of the point (0,2) under the same translation.

Answer 1

Translation vector <4 - 9, 1 + 3> = <- 5, 4>

So, image of point (0, 2) → (0 - 5, 2 + 4) = (- 5, 6)