Hi Tia,
You didn’t specify the desired number of successes, but the command for this in TI-83 or 84:
2nd-VARS-binompdf (n, p, x)
n= total sample size = 4
p= probability of success = 0.2851
x= desired number of successes
I hope this helps.
Tia T.
asked 10/11/24In the binomial probability distribution, let the number of trials be n=4, and let the probability of success be p=0.2851
Hi Tia,
You didn’t specify the desired number of successes, but the command for this in TI-83 or 84:
2nd-VARS-binompdf (n, p, x)
n= total sample size = 4
p= probability of success = 0.2851
x= desired number of successes
I hope this helps.
Thomas K. answered 10/11/24
Top-Rated Math Tutor | Calculus, AMC Competitions, SAT/ACT | 15+ Year
Ti-84 plus:
Cliack 2nd -> VARS (Dist)
A. Binomial PDF
Trials: 4
p = .2851
x= 0,1, 2, 3, 4 You need to choose one of them.
P(x=0) ~~ .2612
P(x=1) ~~ .4167
P(x=2) = .24925 ~~ .2493
P(x=3) = .066266 ~~ .0663
P(x=4) ~~ .0066
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