The specific heat of water is 4.184J/g°C. How many joules of heat will be removed from 2.00 g of water when its temperature drops by 20°C?

Answer 1

For this question, we are asked to find the amount of heat (q) removed from 2.00 g of water when its temperature drops by 20ºC. For this, we will use the formula...

q = mC∆T

q = heat = ?

m = mass of water = 2.00 g

C = specific heat of water = 4.184 J/gº

∆T = change in temperature = 20º

Solving for q we have...

q = (2.00 g)(4.184 J/gº)(20º)

q = 167.36 J (joules) not corrected for significant figures

Since 20º has only 1 sig.fig. the answer might be reported as 200 J (1 sig.fig.)