(3x+3) + (10x - 4) = 90
13x = 91
x = 7
So ∠K = 3x + 3 = 24° and ∠L = 10x - 4 = 66°.
Shelbie C.
asked 09/04/24<k and <l are complementary angles if m<k= (3x+3) and m<l= (10x-4 find the measure of each angle
(3x+3) + (10x - 4) = 90
13x = 91
x = 7
So ∠K = 3x + 3 = 24° and ∠L = 10x - 4 = 66°.
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