Suppose M is a point in the interior of ⦟JKL. If m⦟JKL=35 and m⦟JKM = 9x+10, and m⦟MKL= x+15. What is x?

Answer 1

Suppose M is a point in the interior of ∠JKL. Given m∠JKL=35 degrees, m∠JKM = 9x + 10 degrees, and m∠MKL = x + 15 degrees. To find x, use the fact that the sum of m∠JKM and m∠MKL is equal to m∠JKL:

9x + 10 + x + 15 = 35

10x + 25 = 35

10x = 10

x = 1

Therefore, x = 1.

Answer 2

If you draw this situation out, you notice that m∠JKM and m∠MKL, when added together, gets you m∠JKL through angle addition. Thus:

(9x + 10) + (x + 15) = 35

x = 1

Hope this was helpful.