J.R. S. answered 07/27/24
Ph.D. University Professor with 10+ years Tutoring Experience
1.) how many grams of Fe2O3 can form from 29.2 grams of O2?
In order to obtain Fe2O3 from O2, you obviously will also need some iron (Fe). So, we need to write a correctly balanced equation using Fe and O2 to make Fe2O3:
4Fe + 3O2 ==> 2Fe2O3 .. balanced equation
Next, we will convert 29.2 g O2 to moles of O2 using the molar mass of O2 (32.00 g/mol)
29.2 g O2 x 1 mole O2 / 32.00 g = 0.9125 moles O2
Next, we will use the stoichiometry of the balanced equation to determine moles and then grams of Fe2O3:
0.9125 mols O2 x 2 mols Fe2O3 / 3 mols O2 = 0.6083 mols Fe2O3 (molar mass 159.7 g/mol)
0.6083 mols Fe2O3 x 159.7 g / mol = 97.2 g Fe2O3 (to 3 significant figures)
Parts 2 and 3 are just a repeat of the procedure outlined above.
2.) grams O2 --> moles O2 --> moles Fe2O3 --> grams Fe2O3
3.) 29.2 g O2 x 1 mol O2/32.0 g x 2 mols Fe2O3 / 3 mols O2 x 159.7 g Fe2O3 / mol = 97.2 g Fe2O3