Inactive Tutor answered 02/11/26
25^2= 17^2 +11^2 -2(17)(11)cosD
solve for D
625 = 289+121- 374cosD
215= -374cosD
cosD=- 215/374
D= arccos(-215/374)= about 125.090 degrees
angle between them - 180-125.090= 54.910 degrees
Two forces of 17 N and 11 N have a resultant force of 25 N. What's the angle between the two forces?
Inactive Tutor answered 02/11/26
25^2= 17^2 +11^2 -2(17)(11)cosD
solve for D
625 = 289+121- 374cosD
215= -374cosD
cosD=- 215/374
D= arccos(-215/374)= about 125.090 degrees
angle between them - 180-125.090= 54.910 degrees
Inactive Tutor answered 07/19/24
You can use the Law of Cosines to determine this:
252 = 172 + 112 - 2(17)(11)cos(θ)
625 = 289 + 121 - 374cos(θ)
215 = -374cos(θ)
cos(θ) = -(215/374)
θ = cos-1(-(215/374)) = 125°
Inactive Tutor
You are correct. The 125 degree angle would be 55 degrees if we moved V2 down to the staring point of V1. Sorry for the confusion.07/19/24
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Inactive Tutor
If the forces were pulling on the same object then θ = 180-125=55 deg07/19/24