About 9% of the population has a particular genetic mutation. 188 people are randomly selected. Round both answers to the nearest 2 decimal places.

Question

Find the mean for the number of people with the genetic mutation in such groups of 188.

Find the standard deviation for the number of people with the genetic mutation in such groups of 188.

Answer 1

Use properties of the binomial distribution:

1. Probability of having the genetic mutation, p = 0.09
2. Number of people selected, n = 188

Mean μ of a binomial distribution is:

μ = n * p

Standard deviation σ of a binomial distribution is:

σ = sqrt[n × p × (1 − p)​]

After plugging in the values and calculating, you get that the mean number of people with the genetic mutation is 16.92, and the standard deviation is 3.94.

Hope this was helpful.

Answer 2

Hello!

I have worked out this problem for you in this video. Check out the video and let me know if you have any questions. Take care!

Dr. Christal-Joy Turner