nitrate calculation

Question

If I have different levels of sodium nitrate (0.1g, 0.05g, 0.009g) what are the calculations in order to make one concentrated stock solution? I know that the end number needs to be in microliters.

ex:

9mL x 1/100 = 0.09mL

0.09mL x 1000 = 90 microliters

90microliters x (percentages of solution)

90 x 3% = microliters

90 x 6% = microliters

Answer 1

Your question isn't clear. Are you trying to figure out how many microliters of solvent you need for 0.1g, 0.05 g and 0.009 of NaNO₃ in order have the same concentration of NaNO₃? Or are you asking how to calculate the volume of solvent in order to make different % solutions? Or are you trying to prepare 90 microliters of different % solutions from the different amounts of NaNO₃ (0.1g, 0.05 g, 0.009 g)? Or are you trying to make a single concentrated solution from the 3 different amounts of NaNO₃ and if so, what is that desired concentration and what volume do you want to make? Or is it some other calculation you are looking for?

EDITED RESPONSE:

To make three solutions having the same CONCENTRATION, the amount of liquid solvent will be directly proportional to the mass (grams) of NaNO₃. The 0.1 g will require twice as much solvent as the 0.05 g and 11.1 times as much solvent as the 0.009 g. So, for example, add 1 ml (1000 ul) solvent to the 0.1 g sample. Add 500 ul solvent to the 0.05 g, and add 90 ul to the 0.009 g. This will result in all three solutions have a concentration of ~0.1 ug / ul. As % w/v solutions, these will be 10% solutions.