How much energy (in J ) is lost when a sample of iron with a mass of 28.5 g cools from 75.0 ∘C to 29.0 ∘C ?

Answer 1

To answer this question, we can use the expression q = mC∆T

q = heat = ?

m = mass = 28.5 g

C = specific heat of iron = 0.461 J/gº (looked it up and you may find a different value)

∆T = change in temperature = 75.0º - 29.0º = 46.0º

Solving for q...

q = (28.5 g)(0.461 J/gº)(46.0º)

q = 604 J of heat lost

You might want to put a negative sign in front of this value, but stating that the heat is lost is sufficient. Otherwise, just report the answer as q = -604 J