For a standard normal distribution, find: P(z > c) = 0.6607

Question

For a standard normal distribution, find:

P(z > c) = 0.6607

Answer 1

you can convert the probability over into an actual Z table value using either a normal distribution table or some type of technology like Microsoft Excel. when i do that i find that the Z score for this situation is approximately -0.415.

Answer 2

Hello!

I have worked this problem out in this video for you to review. I hope you find this video to be helpful. If you have any additional questions, please feel free to reach out. Take care!

Dr. Christal-Joy Turner

Answer 3

For a standard normal distribution, to find P(z > c) = 0.6607, we find the z-score corresponding to the cumulative probability of 0.6607. The value of c is the z-score where the area under the normal curve to the right of c is 0.6607.

Using a TI-84 Plus calculator, you type in 2nd --> vars to access the different statistical distributions. Navigate to invNorm with the following inputs: invNorm(0.6607, 0, 1, RIGHT)

After using the TI 84 Plus, online statistical software, or a z-table, you should get -0.4144 rounded to four decimal places. Thus, c = -0.4144.

Hope this was helpful.