Raymond B. answered 06/21/24
Math, microeconomics or criminal justice
secbsin(a+b)
=secb(sinacosb + sinbcosa)
=secbsinacosb + secbsinbcosa
(1/cosb)sinacosb + (1/cosb)sinbcosa
=sina + (sinb/cosb)cosa
= sina+tanbcosa
Laura A.
asked 06/21/24Which of the following is equivalent to secβsin(α+β) for all values of α and β for which secβsin(α+β) is defined?
Raymond B. answered 06/21/24
Math, microeconomics or criminal justice
secbsin(a+b)
=secb(sinacosb + sinbcosa)
=secbsinacosb + secbsinbcosa
(1/cosb)sinacosb + (1/cosb)sinbcosa
=sina + (sinb/cosb)cosa
= sina+tanbcosa
Stephenson G. answered 06/21/24
Experienced Trigonometry Tutor - Precalculus, Algebra 2, Geometry
First, recall that secβ=1/cosβ so we can write:
secβsin(α+β)=sin(α+β)/cosβ
Next, use the angle addition formula for sine:
sin(α+β)=sinαcosβ+cosαsinβ
Substituting this into the expression, we get:
sin(α+β)/cosβ=(sinαcosβ+cosαsinβ)/cosβ
Now, split up the fraction:
(sinαcosβ+cosαsinβ)/cosβ=(sinαcosβ)/cosβ+(cosαsinβ)/cosβ
This simplifies to:
sinα+cosαtanβ
Hope this was helpful.
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