How many sodium ions are used if 2.3 moles of sodium iodide react completely?

Answer 1

Sodium iodide = NaI

Note, for each mole of NaI, ONE mole of Na⁺ and ONE mole of I^- are present

Thus, if 2.3 moles of NaI react, there will be 2.3 moles of Na⁺ ions.

To convert this to the number of Na⁺ ions, we use Avogadro's number as follows:

2.3 mols Na⁺ x 6.02x10²³ ions / mole = 1.38x10²⁴ Na⁺ ions = 1.4x10²⁴ Na⁺ ions