Calculate the [H+] when the pOH = 5.48

Answer 1

There are various ways to answer this problem. Two approaches are shown below.

pH + pOH = 14

pH = 14 - pOH

pH = 14 - 5.48 = 8.52

Now that we have the pH, we can find the [H+] since pH = -log [H+]

[H⁺] = 1x10^-8.52

[H⁺] = 3.02x10^-9 M

[OH-] = 1x10^-5.48 = 3.31x10^-6 M

[H⁺][OH-] = 1x10^-14

[H⁺] = 1x10^-14 / 3.31x10^-6

[H⁺] = 3.02x10^-9 M

NOTE: both of the above calculations ignored the autoionization of H2O. If you are in a more advanced Chem. class, you might want to include this factor.