You pick a letter from the alphabet. What is the probability of selecting a consonant twice in a row?

Answer 1

total letters in the English alphabet is 26

no. of vowels = 5

no. of consonants = 21 which result from (26 - 5)

The probability of picking a consonant twice on the first pick is 21/26 * 21/26 = (21/26)² = 441/676 and since there is no common prime factor as a fraction it will be 441/676

If there is no replacement after the first pick it will be 21/26 * 20/25 = 42/65 and since there is no common prime factor as a fraction it will be 42/65.

Hope this helps.

Answer 2

If drawn with replacement, the answer is:

(21/26)*(21/26).

Without replacement,

(21/26)*(20/25) = (21/13)*(2/5) = 42/65.

This presumes that w and y are both counted as consonants. "Snow" and "why" are two examples of these letters acting like vowels.

Answer 3

26 letters, 5 vowels, 21 consonants (counting y, h, w, and r, all which sometimes act as vowels. a vowel sound is one made with an open mouth no tongue to teeth or mouth roof)

P(2 consonants in 2 draws)= (21/26)(20/25)= (21/13)(2/5)= 42/65

= about 64.62% chance, drawing without replacement

drawing with replacement P(2 consonants) = (21/26)(21/26) = (21/26)^2 = about 65.24%

this assumes the English alphabet

Russian alphabet has 33 letters consisting of 10 vowels 21 consonants and 2 signs

so different probabilities depending on the language