There are 5 red, 6 blue, 7 green, and 3 yellow marbles in a bag. What is the probability of pulling a green marble out?

Answer 1

The probability of pulling a green marble = 7/21 = 1/3.

Answer 2

Probabilty of green or yellow = 10/21

sum of green & yellow divided by sum of all 4 marbles

P(g or y) = 10/21

P(y) = 3/21 = 1/7

P(green) = 7/21 = 1/3

P(b)= 5/21

P(r) = 6/21=2/7