
Rani S. answered 05/13/24
Experienced High School Algebra & Geometry teacher
WHAT DO WE KNOW?
Elinnah can mow her lawn in 3 hours.-----That means in 1 HOUR she mows 1/3 of the lawn
Oseka can mow the same lawn in 2 hours.----That means in 1 HOUR he mows 1/2 of the lawn.
HOW MUCH GETS DONE IN ONE HOUR?
This means if both of them are mowing the lawn at the same time, then in 1 hour:
Elinnah would complete 1/3 of the lawn & Oseka would complete 1/2 of the lawn
1/3 + 1/2 = 5/6
So in 1 hour with their combined effort , 5/6 of the lawn would get mowed.
WHAT WE NEED TO FIND OUT?
We need to find out how much time it will take to mow the lawn if both are mowing at the same time.
Let's call the total time "t" hours.
SOLUTION:
In 1 hour-----> 5/6 of the lawn is completed
In "t" hours-------> 5/6 multiplied by "t" , the full lawn is completed.
So, 5/6t = 1
Multiply both sides by 6:
6 x 5/6 t= 1 x 6
5t=6
Divide both sides by 5:
5t/5 = 6/5
t=6/5 hours
t= 1.2 hour
We need to convert .2 hours into minutes.
1hour ------> 60 minutes.
.2 hours -----> .2 x 60 minutes
.2 x 60 = 12
So the total time needed to mow the lawn with both Elinnah and Oseka mowing together is :
1 hour and 12 minutes