Find what the student did wrong

Question

A student uses the triangle shown to calculate m<A. Find and explain the student’s error

Tan A=24.5/20.7

Tan A=1.184

Tan^-11.184=A

49.81=A

Therefore, m<A≈49.81°

Answer 1

perhaps what is wanted is:

is it certain the terminal point is in 1st quadrant?

if so, then measure of angle A is 49.8 degrees plus k*360 degrees k=0,+1,-1,....

angle 409.8 degrees has same tan(A) value as angle 49.8 degrees.

If the angle can be in third quadrant, -24.5/-20.9 is often simplified to 24.5/20.9

if so then A=49.8 degrees plus k*180 degrees.

Answer 2

A= 49.8056 approximately

if it's a right triangle

or has height 24.5 and base 20.7

a diagram would help, a sketch of the triangle and what 24.5 and 20.7 refer to