A company produces steel rods. The lengths of the steel rods are normally distributed with a mean of 133.7-cm and a standard deviation of 0.7-cm.

Question

Find the probability that the length of a randomly selected steel rod is greater than 135.7-cm. 

P(X > 135.7-cm) = 

Answer 1

Convert 135.7cm to a Z-score: (135.7-133.7)/.7 = 2.86.

Use a Z-table to find the probability of finding a rod less than that Z-score and subtract from 1. 1 -.99788 = .00212