What is the solubility of PbF₂ in a solution that contains 0.0850 M F⁻ ions? (Ksp of PbF₂ is 3.60 × 10⁻⁸)

Answer 1

Same as others you posted.

Ksp = [Pb²⁺][F^-]²

3.60x10^-8 = [Pb²⁺][0.0850]² = 0.007225[Pb²⁺]

[Pb²⁺] = 4.98x10^-6 M