I need some help ASAP

Question

A coffee shop finds on Friday that 38% of its customers ordered a pastry and 20% of its customers ordered both a pastry and coffee. Find the probability a customer ordered coffee, given they ordered a pastry.

Answer 1

This is an application of the definition of conditional probability.

Let A be the event that a customer orders a pastry. Let B be the event that a customer orders a pastry and coffee.

The given information implies that P(A)=0.38 and P(A and B)=0.2. We seek the conditional probability P(B|A). By definition, we have:

P(B|A) = P(A and B) / P(A)

Plugging in the quantities we know, we arrive at P(B|A) = 0.2/0.38, which is approximately 0.5263.

Answer 2

P(p)=.38, P(c&p) = .20

what is P(c/p)? = P(c^p)/P(p) = .2/.38 = 20/38

= 10/19= about .52632

= about 52.63% = about 53%