J.R. S. answered 05/02/24
Ph.D. University Professor with 10+ years Tutoring Experience
Ideal Gas Law:
PV = nRT
P = pressure = 23.11 atm
V = volume in liters = 2.000 L
n = moles = ?
R = gas constant = 0.0821 Latm/Kmol
T = temperature in Kelvin = 27.0ºC + 273.15 = 300.15K
Solving for moles (n) ..
n = PV/RT = (23.11)(2.000) / (0.0821)(300.15)
n = 1.8756 moles = 1.88 moles (3 sig.figs.)
From the given mass (133.0 g) we can determine the molar mass as follows:
molar mass = g / mol = 133.0 g / 1.88 mols = 70.7 g / mole
Since the halogens (F, Cl, Br, I) occur as diatomic molecules (F2, Cl2, Br2 and I2), this most closely corresponds to Cl2 gas with a molar mass of 70.9 g / mole