J.R. S. answered 04/27/24
Ph.D. University Professor with 10+ years Tutoring Experience
Au goes from 0 to +4 oxidation number (it is being oxidized)
N goes from +5 to +4 oxidation number (it is being reduced)
Oxidation half reaction:
Au + HCl ==> HAuCl4
Au + 4HCl ==> HAuCl4 .. balanced for Au and Cl
Au + 4HCl ==> HAuCl4 + 3H+ .. balanced for Au, Cl and H
Au + 4HCl ==> HAuCl4 + 3H+ + 3e- .. balanced oxidation reaction
Reduction half reaction:
HNO3 ==> NO2
HNO3 ==> NO2 + H2O .. balanced for N and O
HNO3 + H+ ==> NO2 + H2O .. balanced for N, O and H
HNO3 + H+ + e- ==> NO2 + H2O .. balanced reduction reaction
Au + 4HCl ==> HAuCl4 + 3H+ + 3e-
3HNO3 + 3H+ + 3e- ==> 3NO2 + 3H2O
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Au + 4HCl + 3HNO3 ==> HAuCl4 + 3NO2 + 3H2O .. BALANCED REDOX EQUATION