what would the SIX trig ratios be if COTX=-1, and SinX=√2/2?

Question

Thank you in advance!

Answer 1

Based on the sin being positive and cot being negative, this must be in the second quadrant. The adjacent side is -1, the opposite side is 1 based on the cot value given and the hypotenuse is √2 based on the sin values given. Therefore using SOH CAH TOA,

sin x = √2/2 (given)

cos x = -√2/2

tan x = -1

cscx = √2

sec x = -√2

cot x = -1 (given)